STDs4YouAnd4Me
Legacy Supporter 8
- Joined
- Sep 11, 2012
Neither, really. Just a bunch of [MC2020]'s next to eachother. The more you add, the higher the odds of hitting the jackpot are.
From my knowledge, the MC2020s have 1 input and 3 outputs. The first input will trigger 1 of the 3 outputs (let's call them A, B, and C). For the purpose of explaining, let's assume that the 'winning route is always going to be A.
When someone tries their luck, if the 1st MC2020 ends up falling on B or C, they'll lose straight away.
If it ends up falling on A, the A output will start a new string of MC2020s and will in essence become the input... MC2020 #2 would need to fall under A... as well as #3, #4, #5... at the end of #5 on the A output will be a transmitter. The Transmitter will send a signal to the receiver, which will drop the loot to the player. No pistons necessary. Just a steady stream of ICs.
In layman's terms, you're rolling a 3 sided dice 5 times and hoping it comes up at 1 every time.
From my knowledge, the MC2020s have 1 input and 3 outputs. The first input will trigger 1 of the 3 outputs (let's call them A, B, and C). For the purpose of explaining, let's assume that the 'winning route is always going to be A.
When someone tries their luck, if the 1st MC2020 ends up falling on B or C, they'll lose straight away.
If it ends up falling on A, the A output will start a new string of MC2020s and will in essence become the input... MC2020 #2 would need to fall under A... as well as #3, #4, #5... at the end of #5 on the A output will be a transmitter. The Transmitter will send a signal to the receiver, which will drop the loot to the player. No pistons necessary. Just a steady stream of ICs.
In layman's terms, you're rolling a 3 sided dice 5 times and hoping it comes up at 1 every time.